A 5L cylinder contained 10 moles of oxyegen gas at 300.Due to sudden leakage,all the gas escaped into atm and cylinder got empty,If Atm p=1atm calculate WD by gas
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OpenStudy (dls):
WD=-p delta V
delta V=Vf-Vi
Vf=0
so delta V =0
so WD=0
o_O
OpenStudy (shubhamsrg):
vfinal = 0 ? o.O
OpenStudy (dls):
all the gas escaped into atm and cylinder got empty :o
OpenStudy (anonymous):
v = nrt/p
OpenStudy (shubhamsrg):
Vfinal = nrT/p
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OpenStudy (shubhamsrg):
yep, exactly
OpenStudy (anonymous):
w= -p(change in volume)
OpenStudy (dls):
wtf why
OpenStudy (dls):
Vf not 0 why?
OpenStudy (anonymous):
v = nrt/p
v= 10*8.314*300/1 = 24942 J
w= -p(change in volume)
w=-1*24942= -24942 or 24.9 kj
this is a different version of your question
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OpenStudy (shubhamsrg):
we are calculating work done by gas.
v initial = 5 (volume occupied by gas in cylinder)
vfinal = nrt/p (volume occupied by gas in air)
OpenStudy (dls):
oh :o thanks!
OpenStudy (shubhamsrg):
(Y)
OpenStudy (anonymous):
good job @shubhamsrg you explain it really easily and simply :)
OpenStudy (dls):
<3
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