Question

Solve x = log9^4.
Can someone explain how to solve these things? :/ X_X

Answer 1

\[loga^m = mloga \Rightarrow \log9^4 = 4\log9\]

Answer 2

exactly as @sachinrajsharma said :)

Answer 3

but I'm supposed to find x, how to do that? :/

Answer 4

that would be what 4log9 equates to....ill do the calculation for you
4log9 = 3.816970038

Thats what x equals :)

Answer 5

x = 4log9 = 4log3^2 = 8log3 now put the value of log3 u get ur answer

Answer 6

Thanks for the answer but I'd like to understand how to solve them, I still don't get it X_X How did you get to 8log3?

Answer 7

remember the equation @sachinrajsharma put up there?

\[\log_{a}^m = m \log_{}a \]

That means when it goes from

x = 4log9

to

x = 4log3^2 (3^2 is just another way of writing 9 right?)

the equation says you multiply the exponent (2) to the log 4log3.....now since you already have 4 as a coefficent....you multiply 4 and 2...to get 8...which leaves you with 8log3

Answer 8

equation didn't come out right...but it's the equation they put up there

Answer 9

Ohhhh ok I see. Sorry I'm kinda slow. And I'm still not sure I understand exactly why x is that number but thanks for explaining.

Answer 10

you're not slow...i'm sure you're very intelligent :)

and x equals that because

x = 4log9

it just say x is equal to whatever 4log9 equates to...

just like x = 2...that says x = 2
x = 6(10)

means x = 60....

so x is whatever 4log9 equals :)

Answer 11

Oh damn. I misunderstood everything about log I guess lol Get it now :) ty

Answer 12

haha good :) and anytime :)