Question

Use the given inverse...
will give a medal :)

Answer 1

whats the inverse

Answer 2

I believe she's still attaching/typing it

Answer 3

@amistre64

Answer 4

THE SETUP FOR IT GOES LIKE THIS

|4 3| |x| = |6|
|2 2| |y| |5|



A^(-1) |4 3| |x| = A^(-1) |6|
|2 2| |y| |5|


|x| = A^(-1) |6|
|y| |5|

Answer 5

.... caps stuck :)

Answer 6

there are some rules you can follow for finding an inverse:

a rule of thumb for a 2x2 is to swap a d and negate b c, then divide by the determinant

Answer 7

\[A=\begin{vmatrix}a&b\\c&d\end{vmatrix}\]
\[A^{-1}=\frac{1}{ad-bc}\begin{vmatrix}d&-b\\-c&a\end{vmatrix}\]

Answer 8

we can stick 6 5 in that to determine formula for x and y now

\[\binom{x}{y}=\frac{1}{ad-bc}\begin{vmatrix}6d-5b\\-6c+5a\end{vmatrix}\]

Answer 9

hmmm, i missed that they GAVE the inverse already sooo

just 6 5 the inverse :)

Answer 10

so x= 6 and y=5 correct ?

Answer 11

soryr im a bit confused ehre the solution cant be x= 6 and y= 5.. :s @amistre64

Answer 12

@jim_thompson5910

Answer 13

\[Ax=b\]
\[A^{-1}Ax=A^{-1}b\]
\[A^{-1}A=1;~therefore\]
\[x=A^{-1}b\]
you should already know how to multiply a matrix by a column vector

they give you \(A^{-1}\) and \(b\)

Answer 14

@jim_thompson5910