How do you simplify this? (2x^2 * x)^3 I used * for multiplication
Basically do the FOIL method twice because you have (2x^2 * x)(2x^2 * x)(2x^2 * x) You just gotta multiply it out
how do you multiply 2x^2 by x?
\(2x^2 \cdot x=2x^3\). Now calculate \((2x^3)^3\) @johnweldon1993: I think you made a mistake about the FOIL method.
@ZeHanz thank you for pointing that out....FOIL wont work here sorry about that @stabar
@stabar : remember: powers are just shorthand for repeated multiplication: \(a \cdot a=a^2\)
So \(2x^2 \cdot x=2 \cdot x\cdot x\cdot x=2x^3\)
right I get that...just not how I multipl that by x when i dont have a number for x
You do not have to know how much x is. You cannot work out how much x*x is. You only can shorten it a little by writing it as x².
ok so then 2x^2 * x would be 2x^3
Right...remember you can multiply any numbers together...remember that x....can also be written as 1x^1 And when multiplying eponents...you add them so yes 2x² * x WOULD be 2x^3
so now all I have to do is work this out right?: (2x^3)(2x^3)(2x^3)
Now the last step: \((2x^3)^3=2x^3 \cdot 2x^3 \cdot 2x^3=2 \cdot 2 \cdot 2 \cdot x^3 \cdot x^3 \cdot x^3=...\)
You can take the 2's apart and also the factors x³.
So I got 8x^9 is that right?
Yes! You got it!
Thank you
YW!
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