Generate the first five terms in the sequence using the explicit formula. yn = β5n β 5
Just plug in numbers into the equation for n such as n=0, n=1, n=2, n=3, n=4
Then what?
Then those are your five terms....
Well I did that but I did not get any of the numbers that match the multiple choice, I guess I'm just really stupid in the mornings
What did you get for y when n=0?
I guess I can figure t out from here thank you
-30
How?? You just plug in so that y= -5*0-5 And then you end up with y=-5
1. Generate the first five terms in the sequence using the explicit formula. yn = β5n β 5 (1 point) (0 pts) β30, β25, β20, β15, β10 (0 pts) 30, 25, 20, 15, 10 (1 pt) β10, β15, β20, β25, β30 (0 pts) 10, 15, 20, 25, 30 1 /1 point 2. What is the 15th term in the sequence using the given formula? cn = 3n β 1 (1 point) (0 pts) 14 (0 pts) 57 (1 pt) 44 (0 pts) β44 1 /1 point 3. Write a recursive formula for the sequence 7, 13, 19, 25, 31, ... Then find the next term. (1 point) (1 pt) an = anβ 1 + 6, where a1 = 7; 37 (0 pts) an = anβ 1 + 6, where a1 = 37; 7 (0 pts) an = anβ 1 β 6, where a1 = 6; β23 (0 pts) an = anβ 1 β 6, where a1 = 7; β8 1 /1 point 4. Write a recursive formula for the sequence 7, 4, 1, β2, β5, .... Then find the next term. (1 point) (0 pts) an = anβ1 β 3, where a1 = β8; 7 (1 pt) an = anβ1 β 3, where a1 = 7; β8 (0 pts) an = anβ1 + 3, where a1 = β3; 22 (0 pts) an = anβ1 + 3, where a1 = 7; β8 1 /1 point 5. Write an explicit formula for the sequence 8, 6, 4, 2, 0, ... Then find a14. (1 point) (0 pts) an = β2n + 10; β16 (0 pts) an = β2n + 8; β18 (0 pts) an = β2n + 8; β20 (1 pt) an = β2n + 10; β18 1 /1 point
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