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Solve for x x= log base e radical e x=_____a^0
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I think this is what you mean:\(x=\ln \sqrt{e}\)
x +(log base e) radical 3
To solve it, write \(\sqrt{e}=e^{\frac{1}{2}}\)
x = (log base e) radical 3
this is what i mwant x = log (base e) radical 3
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meant*
OK, "log base e" is ln, so you have: \(x=\ln \sqrt{3} \Leftrightarrow x=\ln 3^{\frac{1}{2}}\)
There is a rule for logarithms that says: \(\log_{a}b^k=k \cdot \log_{a}b\). You can use it here.
So \(x=\dfrac{1}{2} \ln3\)
Or, if you wish: \(x=\dfrac{1}{2}\log_{e}3\)
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thank you for that formula thnks
YW!
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