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What is the mass of Aluminum needed for 625mL of chlorine at 40oC at a pressure of 2.5 atmospheres when reacting to form Aluminum chloride: 2 Al + 3 Cl2 à 2 AlCl3
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use the IGL to turn the pressure, volume, and temp of Cl2 into moles of Cl2, then use the balanced reaction to get moles of Al.
PV=nRT is the formula to go to get the moles of chlorine just be sure of the units used
thank you guys very much!
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