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Chemistry 7 Online
OpenStudy (anonymous):

     What is the mass of Aluminum needed for 625mL of chlorine at 40oC at a pressure of 2.5 atmospheres when reacting to form  Aluminum chloride:     2 Al  + 3 Cl2  à 2 AlCl3

OpenStudy (jfraser):

use the IGL to turn the pressure, volume, and temp of Cl2 into moles of Cl2, then use the balanced reaction to get moles of Al.

OpenStudy (anonymous):

PV=nRT is the formula to go to get the moles of chlorine just be sure of the units used

OpenStudy (anonymous):

thank you guys very much!

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