Question

URGENTLY needed


AOB is a diameter of the circle and AC = BC, then
angleCAB is equal to

Answer 1

Friends i have done , but doubt ki mera solution is correct or not
Since, AOB is the diameter,
∠ACB = 90 (angles in a semi-circle is a right angle)
ΔABC is an isosceles triangle [AB = BC(Given)]
∴ ∠CAB = ∠ABC (isosceles triangle property)
but, ∠CAB + ∠ABC + ∠ACB = 180 (angle sum property of a triangle)
∠CAB + ∠ABC + 90= 180 [∠ACB = 90(proved)]
2∠CAB + 90 = 180 [∠CAB = ∠ABC (proved)]
2∠CAB = 180 - 90 = 90
∠CAB = 90/2 = 45
∠CAB = 45

Answer 2

yes ur solution is correct

Answer 3

@Ahmad_Shadab
thank you so much

Answer 4

This illustration also indicates that your answer is correct.