Question

solve factoring 5x^2 +12x-44=0

Answer 1

here is my method

for a quadratic

\[ax^2 + bx + c = 0\]

multiply a and c so in your question 5 x -44 = - 220

find the factors that add to 12 22, -10

then write the binomials as

(ax + factor 1)(ax + factor 2)
-------------------------- = 0
a

so you get

\[\frac{(5x -10)(5x + 12)}{5} = 0\]

remove the common factor from the 1st binomial

\[\frac{5(x - 2)(5x + 22)}{5} = 0\]

cancel the common factor for the solution.

Answer 2

@campbell_st wow! I like that method it's alot easier than guess and check

Answer 3

you can also use the quadratic formula to solve for x, then you can use the zero product property to rewrite as a factorization

Answer 4

and it works every time...

Answer 5

for example, if you solved x^2 + 5x + 6 = 0 for x using the quadratic formula, you would get

x = -3 or x = -2

that's equivalent to

x+3 = 0 or x+2 = 0

which is the same as

(x+3)(x+2) = 0

Answer 6

another method is the dicriminant method

evaluate the discriminant 1st elps to determine how difficult the problem is

so in jims problem its

25 - 24 = 1

then add or subtract b

(-5 + 1)/2 and (-5 -1)/2

but for me... I'm happy using the method above...

Answer 7

i need to get two solutions

Answer 8

yes so you have the factorised from of the quadratic

(x -2)(5x + 12) = 0

so all you need to do is solve

x - 2 = 0

and

5x + 12 = 0

hope this helps

Answer 9

so the first one solution is -2 i dont get the second on2

Answer 10

First subtract 12 from both sides

5x + 12 = 0

5x + 12-12 = 0-12

5x + 0 = -12

5x = -12

what's next?

Answer 11

5/-12 i think

Answer 12

you have it flipped

Answer 13

it should be -12/5

Answer 14

because you would divide both sides by 5