Solve the equation. Check the solution. -2/x+4 = 4/x+3
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
please help me do this problem
OpenStudy (anonymous):
well first subtract 3 from both sides
OpenStudy (anonymous):
so -2/x+1 = 4/x?
OpenStudy (anonymous):
now add 2/x on both sides
OpenStudy (anonymous):
4 = 6/x+3?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
hold on is your original equation this \[\frac{ 4 }{x+3 }\]
OpenStudy (anonymous):
or is it the way you have it?
OpenStudy (anonymous):
it's the way I had it
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
ok
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
any way how did you get 4=6/x+3
OpenStudy (anonymous):
wasn't I supposed to add 2/x on both sides?
OpenStudy (anonymous):
yes but what is -2/x+2/x
OpenStudy (anonymous):
where did that come from?
OpenStudy (anonymous):
ok so let's go back we had \[\frac{ -2 }{ x }+1=\frac{ 4 }{ x }\] if we add 2/x to both sides it looks like this\[\frac{ -2 }{ x }+1+\frac{ 2 }{ x }=\frac{ 4 }{ x }+\frac{ 2 }{ x }\]
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
now combine like terms
OpenStudy (anonymous):
actually the problem is different, let me make the equation
OpenStudy (anonymous):
\[-2/x+4 = 4/x+3\]
OpenStudy (anonymous):
is it \[\frac{ -2 }{ x+4 }=\frac{ 4 }{ x+3 }\]
OpenStudy (anonymous):
yes, I'm not sure how to exactly make it like that though lol
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
just to make it more clear next time just put everything that is in the bottom portion of the fraction in parentheses like this -2/(x+4)
OpenStudy (anonymous):
but any back to the problem. Now you want to cross multiply
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
let me know what you got after cross multiplying
OpenStudy (anonymous):
(-2x+3)/4x+4?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
that's close but you forgot to multiply 4*4 on the right side and 3*3 on the left side also they should equal each other not be in a fraction. \[3(x+3)=4(x+4)\]
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
now distribute the 3 on the left side and the 4 on the right
OpenStudy (anonymous):
would we subtract 3 from both sides first?
OpenStudy (anonymous):
no just distribute each side first
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Do you remember the distributive property
OpenStudy (anonymous):
no, how was it again?
OpenStudy (anonymous):
a(b+c)=a*b+a*c
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
3*x+3*3 = 4*x+4*4?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ok just simplify that. What is 3*3 and what is 4*4
OpenStudy (anonymous):
9 and 16
OpenStudy (anonymous):
3*x+9 = 4*x+16
OpenStudy (anonymous):
now subtract 3x from both sides
OpenStudy (anonymous):
9 = x+16
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
what do you think comes next
OpenStudy (anonymous):
7?
OpenStudy (anonymous):
but it doesn't match the original equation
OpenStudy (anonymous):
how did you get that ?
OpenStudy (anonymous):
oh wait -7
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
what do you mean it doesn't match the original equation
OpenStudy (anonymous):
if you substitute -7 for x, it won't equal the same amount for both sides
OpenStudy (anonymous):
do you know why?
OpenStudy (anonymous):
oh because earlier i accidentally wrote in 3(x+3) instead of -2(x+3)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so just solve for -2(x+3)=4(x+4)
OpenStudy (anonymous):
distributive property?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
-2*x+-2*3 = 4*x+4*4?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
keep going
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
add 2x to both sides?
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
oh wait, simplify
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yea simplify
OpenStudy (anonymous):
-2x -6 = 4x+16
OpenStudy (anonymous):
then -6 = 6x+16?
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
then add 6 to both sides?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
or subtract -16 from both sides?
OpenStudy (anonymous):
-22=6x?
OpenStudy (anonymous):
good
OpenStudy (anonymous):
so -11/3
OpenStudy (anonymous):
yes and that is definitely correct because I checked
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ok, thank you...I'll give you best response =)
OpenStudy (anonymous):
LMAO you better I'm the only responder
OpenStudy (anonymous):
lol, could you help me with one last word problem?
OpenStudy (anonymous):
ok but we're gonna do this one faster because an hour was way too long for the last problem
OpenStudy (anonymous):
yeah it should be much quicker
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
The speed of the current in a river is 6 mph. A ferry operator who works that part of the river is looking to buy a new boat for his business. Every day, his route takes him 22.5 miles each way against the current and back to his dock, and he needs to make this trip in a total of 9 hours. He has a boat in mind, but he can only test it on a lake where there is no current. How fast must the boat go on the lake in order for it to serve the ferry operator’s needs?
OpenStudy (anonymous):
What is this a physics problem?
OpenStudy (anonymous):
algebra 2
OpenStudy (anonymous):
dude I'm not to sure about this one sorry.
OpenStudy (anonymous):
oh, that's how I felt when I read it =/
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Good Luck
OpenStudy (anonymous):
thanks, I'll try to open a question with it and have a great day :)