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OpenStudy (anonymous):
\[Find dr/d \theta. r=\sin (4-2\theta)\]
OpenStudy (anonymous):
@zepdrix
OpenStudy (anonymous):
ambra te paundi hai udariyan
zepdrix (zepdrix):
Hmm so what would the derivative of \(\large \sin\theta\) be?
This is another one of those problems where we'll have to work with the chain rule. :)
OpenStudy (anonymous):
phul koi vilayti ala lae gaya udd main reh gaya kyarian
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OpenStudy (anonymous):
cos theta
OpenStudy (anonymous):
ur previous question was solved @lovesit2x
OpenStudy (anonymous):
ho attiye kapurthaliye
OpenStudy (anonymous):
yes it was, thanks for your help @mathsmind
zepdrix (zepdrix):
Yes good!
Since the inside of the sine is more than just \(\large \theta\), we have to apply the chain rule, multiplying by the derivative of the inside.
\[\huge r'=\cos(4-2\theta)\color{royalblue}{\left(4-2\theta\right)'}\]
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OpenStudy (anonymous):
cos(4-2theta) (-2) ?
zepdrix (zepdrix):
Understand the process? We took the derivative of sine, which gave us cosine (with the same contents inside of it). And then we make a copy of the inside, and multiply by it's derivative.