Question

H(t) = −16t2 + vt + s
A firecracker shoots up from a hill 150 feet high with an initial speed of 110 feet per second. Using the formula H(t) = −16t2 + vt + s, approximately how long will it take the firecracker to hit the ground?

I know that H(t)=0
v=110 s=150

So I have: 0 = -16^2 + 110t + 150
a = -16 b = 110 c = 150

x = -b/2(a)
x = -110/2*-16
x = 3.4375

The only coordinates I have are (0,0) and (3.4375,0) which are on the same line when they are graphed. But I don't have that third coordinate that will make the parabola. Without that, I'm not sure how to get the answer.

Answer 1

u need to find t

Answer 2

so ur x is t

Answer 3

simple differentiate the function then find the max/min you'll find the third point - ^

Answer 4

then plug the value of t in the main function to get the 3rd coordinate, take care

Answer 5

I found it! Thank you!

Answer 6

you're more than welcome!