Question

for the given equation list the intercepts and test for symmetry y=-8x/x^2+4

Answer 1

the only intercept is when -8x = 0

which is when x = 0

the the x intercept is 0, and y- intercept is 0.

the function is odd since

\[f(-x) = \frac{-8(-x)}{(-x)^2 + 4} = \frac{8x}{x^2 + 4} = -f(x)\]

so the curve has rotational symmetry about (0, 0)

Answer 2

Thank you!!!!