I need help with the substitution part of the differential equation (ln(y))^7*dy/dx=(x^7)y
So, you already got to this point: \( \displaystyle \frac{( \ln y )^7}{y} \; \text{d}y = x^7 \; \text{d}x \) ?
Yes and I am not sure if I could integrate both sides or if I have to substitute anything in.
Well, the right side integrates fairly nicely. The left side, if we integrate this: \( \displaystyle \int \frac{ (\ln y)^7 }{y} \; \text{d}y \) Recall that the derivative of ln y = 1/y. So, we have the function and its derivative here in the integral...
But since it is raised to the power of 7 make it so you can do that?
Even tho it is raised to that power, we are able to make this substitution as long as we are consistent with our substitution, u = ln y; du = 1/y dy. It becomes: \( \displaystyle \int u^7 \; \text{d}u \) Because we have everything covered in the problem, essentially.
The du is dy/y, and u^7 is the same as (ln y)^7
Ok I think was making a mistake with the substitution thanks.
You're welcome! :)
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