Given 10.8 grams of substance Y, if the substance absorbs 231 kilojoules of energy, and the specific heat of the substance is 6.55 J/g degrees Celsius, what is the change in temperature?

Question

chmvijay · Answer

Q=M*C*Delta T
u know Q=231Kja nd M=10.8 g ,C= specific heat of that material=6.55J/g
find Delta T

anonymous · Answer

Is the answer 3.625? If so, how do you get there?

chmvijay · Answer

3.265 i think

chmvijay · Answer

Delta T=Q/M*C
            =231/10.8*6.55

anonymous · Answer

Can you show me the steps to get this? I get a much higher number because I converted 231 kJ to 231000 J. Is that not necessary?

chmvijay · Answer

yaaa u can convert it !!

anonymous · Answer

So, would the answer be 3,625 degrees Celsius? That seems awfully high

chmvijay · Answer

yaaa

anonymous · Answer

So which is right ?

chmvijay · Answer

to convert it into Joules is correct whatever the value may be

chmvijay · Answer

bcoz J/g*J/g here all units should cancel right

anonymous · Answer

The options I'm given are:
a. -3.625 degrees Celsius
b. 3.625 degrees Celsius
c. 140 degrees Celsius
d. -140 degrees Celsius

 I suppose that 3.625 is the closest to the right answer, right?

chmvijay · Answer

yaa its looks like that

anonymous · Answer

Okay, well thank you for all your help and your time in helping me! I appreciate it very much.

chmvijay · Answer

ur welcome you  with such a good problems :)