Question

Please Help....
Multiply and simplify to lowest terms...

Answer 1

\[\frac{ 3y }{ y(y-1) } + \frac{ 2 }{ y-1 }\]

Answer 2

@robtobey can you please help me out?

Answer 3

@JazminZamarripa The algebraic expression in your question shows the two terms are added. However your question asks to multiply. Can you please check the original question?

Answer 4

Thats the question its confusing can you please help me? @kropot72

Answer 5

\[\frac{a}{b}+\frac{c}{d}=\frac{a d+b c}{b d} \]\[\frac{3y(y-1)+2y(y-1)}{y(y-1)(y-1)}\text{= }\frac{5}{y-1}\]

Answer 6

Thank you very much i appreciate it can i ask you one more question please? @robtobey

Answer 7

OK

Answer 8

Simplify the expression and assume all variables are real numbers \[\sqrt[3]{253(x+1)^{3}}\]

Answer 9

@robtobey thank you for helping me

Answer 10

\[\sqrt[3]{253(x+1)^3}=(x+1)\sqrt[3]{253}\]253=11*23, 11 and 23 are prime numbers.

Answer 11

@JazminZamarripa

Thank you for the medal.

Answer 12

Thank you for your help and just to make sure the answer is 11? @robtobey

Answer 13

No, 11 is not the answer.
The number part is\[\sqrt[3]{253} \text{ or } 6.3247\]No further simplification of the radical expression is possible.

Answer 14

ok thank you @robtobey

Answer 15

You're welcome.