how do i simplify x^2+3x+2/x+2 and find the vertical asymptotes? so far im at [(x+1.5)(x+1.5)-.25]/(x+2) help! :[

Question

directrix · Answer

Is this the following:  (  x^2 + 3x + 2 ) / (x+2)  = f(x)  ?

anonymous · Answer

yes /:

anonymous · Answer

i think its (x+3/4)(x+3/4)-1/8?? i don't know so the vertical asymp is when i solve for 0?

directrix · Answer

(  x^2 + 3x + 2 ) / (x+2)  = f(x)

[ (x + 2) * (x + 1) ] / (x + 2)   = f(x)

@jbongarz   Why did you factor the numerator as you did? I'm just wondering.

anonymous · Answer

no idea. i tried to divide everything by 2. i don't know what i'm doing. lol

directrix · Answer

I don't think there will be a vertical asymptote.

anonymous · Answer

thank you so much!

directrix · Answer

Provided x is NOT -2, then [ (x + 2) * (x + 1) ] / (x + 2) =  x + .

So, we are graphing y = x + 2 where x ≠ -2.

directrix · Answer

The graph is a line (y = x + 2) with a hole in it at the point (-2, 0).

That is not identical to the graph y = x + 2 which is a "solid" line.

anonymous · Answer

so then there would be an oblique asymp?

directrix · Answer

No asymptotes at all.

directrix · Answer

http://tinyurl.com/atnbzwc

directrix · Answer

@jbongarz