Question

2√(x+1) - [6/√(2x-1)] =0
Find x.

Answer 1

first add \(\frac{6}{\sqrt{2x + 1}}\) to both sides, and then square both. you will be left with no radicals

Answer 2

what?

Answer 3

can you add \(\frac{6}{\sqrt{2x -1}}\) to both sides?

Answer 4

2√(x+1) = [6/√(2x-1)]

Answer 5

that's right. now square both sides

Answer 6

4x+4 = 36/ (2x-1) ?

Answer 7

x=2 or x= -2.5 (rej.) ??

Answer 8

\(\huge \color{Pink}\checkmark \)

Answer 9

@dmezzullo never mind, you have tried your best:) you have helped me already:) thanks:)
@hartnn thanks:)

Answer 10

2√(x+1) - [6/√(2x-1)] =0
2√(x+1)=[6/√(2x-1)]
squaring both sides we get;
4(x+1)=36/(2x-1)
cross multiplication you will get;
4(x+1)(2x-1)=36
(4x+4)(2x-1)=36
8x^2-4x+8x-4=36
8x^2+4x-4-36=0
8x^2+4x-40=0
4(2x^2+x-10)=0
2x^2+x-10=0
on solving you will get x=2 and x= (-2.5 ;this value is neglected as x cant be negative)
therefore the value of x=2 is your answer
(Note:you can check your answer by putting the value of x=2 in your given equation as well)