Question

The straight line y=2x+k meets the parabola y=x^(2)+6x-5 at two distinct points A and B.
(a) Find the range of values of k.
(b) Suppose the coordinates of A are (2,11).
(i) Find the value of k.
(ii) Find the coordinates of B.

Answer 1

can you solve y=2x+5 and y=x^(2)+6x-5 simultaneously ?

Answer 2

put y=2x+5 in y=x^(2)+6x-5

Answer 3

that should be 2x+k not 2x+5

Answer 4

yes.

Answer 5

so , what u get ?

Answer 6

no, that should be 2x+k.............
i got the answer wrongly, the answer is k>-9 but my answer is k>-16...

Answer 7

can you show your work?

Answer 8

yes, that was typo...i meant 2x+k only.

Answer 9

ohh, wait.....maybe i get the wrong question..................

Answer 10

so, you already knew that you need to make discriminat >0 for the quadratic you gonna get ?

Answer 11

*discriminant damn

Answer 12

yup, i got the answer of part a now:)

Answer 13

so, A = (2,11)
which makes x=2, can u get 'k' now ?

Answer 14

but part b.....
sub x=2 and y=11 into the equation y=2x+k.
11=2(2)+k
k=11/4

Answer 15

11 = 4+k
k= 11-4 =...

Answer 16

nani 0.0?!
oh my god

Answer 17

happens with all of us :P

Answer 18

what about B ?

Answer 19

know how to find it ?

Answer 20

umm.....

Answer 21

i got many decimal places......

Answer 22

x^2+6x-5 = 2x+7
solve this quadratic.

Answer 23

one root = 2, other root =... ?

Answer 24

x=2 or x=-6
y=11 or y=-5 ??

Answer 25

\(\huge \color {red}\checkmark\)

Answer 26

thanks

Answer 27

welcome ^_^