Question

any one help me with grouping factors?

Answer 1

where is the question ?!

Answer 2

1. x^3 + 2x^2 + 4x + 8
2. 2x^3 - 6x^2 + 3x - 9

Answer 3

Take the bigger power with each other & The smaller power with each other
1- \[(x^3-2x^2) + (4x+8)\]
Then take the common factor
\[x^2(x-2) +4(x+2)\]
Then group the common factors with each other
\[(x^2+4) (x-2)(x+2) =0\]
therefore \[x=+or-2\]

Answer 4

its x^3 + 2x^2 not x^3 - 2x^2

Answer 5

it will be the same steps
bt instead of +or-2 it will be -2 Only

Answer 6

2x^3 - 6x^2 + 3x - 9 = 2x^2 (x - 3) + 3(x - 3)

(x-3) is a common factor

2x^3 - 6x^2 + 3x - 9 = 2x^2 (x - 3) + 3(x - 3) =

(x-3)*(2x^2 +3) --> check my work, please

Answer 7

x^3 + 2x^2 + 4x + 8 =

x^2(x + 2) + 4( x+2) =

(x +2) is a common factor

(x + 2) ( x^2 + 4) ---> check my work, please.

Answer 8

Question? @crissy126

Answer 9

none thx for helping

Answer 10

Happy to help.

Answer 11

@Directrix how do you use a diamond problem to factor: x^2 - 2x + 1

Answer 12

@crissy126