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Mathematics 13 Online
OpenStudy (anonymous):

An unbiased coin is tossed 5 times. Find the chance that head will appear exactly 3 times

OpenStudy (anonymous):

u can use fractions or percents

OpenStudy (anonymous):

cant understand

OpenStudy (anonymous):

there are 10 coins the chances of getting 5 heads out of 10 would be 5/10 =1/2

OpenStudy (anonymous):

the 10 being a denominator and the 5 being the nominator 5is the chances out of 10

OpenStudy (anonymous):

so 3/5 ah

OpenStudy (anonymous):

yes fractions or there are percents

OpenStudy (anonymous):

the answer is 5/16

OpenStudy (anonymous):

probably i'm not really good with this but yes make sure u put both on the paper by using the equal sign after your first fraction and then the 5/16 after the equal sign

OpenStudy (anonymous):

k

OpenStudy (anonymous):

so any q.?

OpenStudy (anonymous):

In a party every person shakes hands with every other person. If there were a total of 120 handshakes in the party then what is the number of persons present in the party?

OpenStudy (anonymous):

wow ,hmmm.....let me think

OpenStudy (anonymous):

huh i came up with something but, it's not the correct number of handshakes it's one more handshake then counted for

OpenStudy (anonymous):

did u hav any thoughts for it??

OpenStudy (anonymous):

don't divide it in half but try x numbers but they have to be the same number timing like 10x10=100

OpenStudy (anonymous):

yes.

OpenStudy (anonymous):

its15

OpenStudy (anonymous):

or 16

OpenStudy (anonymous):

the # ur trying to get is 120

OpenStudy (anonymous):

15into16 is 120

OpenStudy (anonymous):

i tryed 11x11 and got 121

OpenStudy (anonymous):

thanks a lot

OpenStudy (anonymous):

make sure u close this q. and ur welcome

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