Ask your own question, for FREE!
Mathematics 16 Online
Parth (parthkohli):

How to factor this?\[4x^4+12x^3y+4x^3−7x^2y^2+4x^2y−25x^2−48xy^3−15xy^2−25x−36y^4−18y^3 \\ +100y^2+50y\]

OpenStudy (experimentx):

looks like this isn't homogeneous ... try putting vales of x and y ... and try getting zeros and try reducing it using fundamental theorem of algebra. factoring it is very tough job, you might also wanna try comparing with \[ (a_1x^4 + ... +a_4x)(b_1 y^4 + .... + b_4y) \]

OpenStudy (experimentx):

woops!! it wasn't of that form.

Parth (parthkohli):

Hmm, yes, you are right. I can expand what you wrote. But I am too lazy to do so!

Parth (parthkohli):

I think that it's of the form you wrote...

Parth (parthkohli):

Oh wait, yes.

OpenStudy (experimentx):

no ... that would give x^4 y^4

OpenStudy (experimentx):

same here ... if I can do it then it should be easy. If it's rigorous ... then i prefer W|A

Parth (parthkohli):

\[(a_1 x^2 + a_2 xy + a_3 y^2)(b_1 x^2 + b_2 xy + b_3 y^2)\]?

OpenStudy (experimentx):

no not that either ... you need constant on one term.

OpenStudy (experimentx):

and there needs to be separate 'x' and 'y' terms

OpenStudy (dan815):

maybe u can find the factoring numbers from pascal triangle or some where else it looks like a very general 4th degree polynomial factorization

OpenStudy (experimentx):

this isn't homegeneous

OpenStudy (dan815):

how do u know if its homogenous?

Parth (parthkohli):

Do you think it's a perfect square? Because the abs of the coefficients of \(x^4\) and \(y^4\) are perfect squares.

OpenStudy (experimentx):

there is cube over there

OpenStudy (experimentx):

best of luck!! I am not doing this! definitely give medal whoever does it.

OpenStudy (experimentx):

most likely it should be of the form \[ (a_1 x^2 + a_2 xy + a_3 y^2+a_4 x + a_5 y)(b_1 x^2 + b_2 xy + b_3 y^2 + b_4)\] gotta go .. best of luck!!

Parth (parthkohli):

Bye bye :-)

OpenStudy (dan815):

watcha doingg

OpenStudy (dan815):

is it possible to do a whole bunch of sythentic division with (x-a) and (y-b)

OpenStudy (anonymous):

What I got so far is that it's the product of three trinomials (ax + by + c)(dx + ey + f)(gx + hy + i)(jx + ky + l), working on seeing if I can factor it from there :)

OpenStudy (anonymous):

four trinomials*

OpenStudy (anonymous):

Gonna take a month brb

OpenStudy (experimentx):

either c or f or i or l has to be zero

OpenStudy (experimentx):

note that there is no constant term.

OpenStudy (anonymous):

Yeah

OpenStudy (anonymous):

Expanding it is still a lot of work tho :P

OpenStudy (experimentx):

good luck!! I am super busy today

OpenStudy (dan815):

was it one of the bernoullis that said they found an equation to solve the 4th degree polynomials or was it fermat

OpenStudy (anonymous):

I'm so happy I bought 2 colors of pens right now

OpenStudy (dan815):

that reminds me i am gonna buy one of those pens for the computer then i can draw stuff on here :)

OpenStudy (experimentx):

to solve 4th degree polynomial you use Ferrari's method (single variable). I use pencil for math ... but i keep losing it.

OpenStudy (anonymous):

I use frixion pens, they're erasable :3

OpenStudy (experimentx):

yeah .. that would make things easy.

OpenStudy (experimentx):

also you can use Wolfram mathematica to factorize the above eqaution

OpenStudy (experimentx):

gotta concentrate on work ... see you later guys!!

OpenStudy (anonymous):

O god why didn't I

OpenStudy (experimentx):

if you can without it then Don't ... it's good for practice.

OpenStudy (anonymous):

This thing is 9 lines long atm, haven't combined like terms yet

OpenStudy (experimentx):

try putting x=0 and see what you get, and also y=0 and what you get.

OpenStudy (anonymous):

I give up lol

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!