Equation containing a radical? The answer would be great, but I also want someone to show me how to solve it. Please help!!

Question

anonymous · Answer

$$\frac{ 6 }{ \sqrt{3+2} }$$

phi · Answer

that is not an equation.  but you can re-write it
I would simplify 3+2 

then multiply top and bottom by the sqrt(5)  to "rationalize" it

anonymous · Answer

Equation could be linear or quadratic. Let's have a linear equation with a radical
$$x-\sqrt 2=2$$
Can you solve it?

anonymous · Answer

$$x = 2 + \sqrt{2}$$
?

anonymous · Answer

yes, you're correct.

anonymous · Answer

Okay, well then how should I simplify the one I gave?

phi · Answer

simplify 3+2 

then multiply top and bottom by the sqrt(5)  to "rationalize" it

anonymous · Answer

$$\frac{ 6\sqrt{5} }{ 5 }$$?
But that isn't one of the multiple choice options I've been given.

phi · Answer

what are your choices ?

anonymous · Answer

A)$$\frac{ 4 }{ \sqrt{3} }$$
B)$$12 - 6\sqrt{3}$$
C)$$\sqrt{3-2}$$
D) 3

phi · Answer

is the problem really
$$ \frac{6}{\sqrt{3} +2} $$
?

phi · Answer

multiply top and bottom by the "conjugate"  
$$ \sqrt{3}-2 $$
this is like multiplying (a+b)(a-b)= a^2 - b^2 which gets rid of the radical in the bottom
(but moves it to the top)

anonymous · Answer

Oh my goodness, I didn't see that! Sorry to have wasted your time, and thank you for pointing out that mistake to me. Au revoir