Find the derivative: f(x)= 5 secx tanx
I already tried like this
dx/dy= 5(secx tan^2x + secx (1+tan^2x))
dx/dy= 5 (2secxtan^2x +secx)
dx/dy= 5secx (2tan^2x+1)

What's wrong in my answer?
How to get this answer: dx/dy= 5secx (2sec^2x -1)

Question

Find the derivative: f(x)= 5 secx tanx
I already tried like this
dx/dy= 5(secx tan^2x + secx (1+tan^2x))
dx/dy= 5 (2secxtan^2x +secx)
dx/dy= 5secx (2tan^2x+1)

What's wrong in my answer?
How to get this answer: dx/dy= 5secx (2sec^2x -1)

dan815 · Answer

i hate these sec and cot bullpellet just look it up lol 
other side
sec = 1/cos and tan = sin/cos
so sin/cos^2
u substitution

dan815 · Answer

oh u want derivative
i thought u wanted integral my bad lol

dan815 · Answer

well u can still do it that way just ignore u substitution comment

dan815 · Answer

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