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Find the derivative f(θ)= secθ^2 How to solve this?
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use the chain rule
d/dx f(g(x))=f'(g(x))g'(x)
f(θ) = y f'(θ) = dy/dθ u = sec(θ) du/dθ = sec(θ)tan(θ) y = u² dy/du = 2u Then, f'(θ) = 2usec(θ)tan(θ) ==> 2(sec²(θ))sec(θ)tan(θ) ==> 2sec³(θ)tan(θ) I hope this helps!
f(x)=x^2 g(th)=sec th
|dw:1362873411456:dw| |dw:1362873506755:dw|
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