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I have the anser can someone check me please. Find the derivative of the following. m is a constant. f(x)=4x^2m
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The answer I got is 8x^m
Is the original problem \[\Large f(x) = 4x^{2m}\]
yes
ok so you would bring down the exponent, then multiply it with the coefficient 4 to get 8m that's the new coefficient
then you would subtract 1 from 2m to get 2m-1 that's the new exponent
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so \[\Large f(x) = 4x^{2m}\] \[\Large f^{\prime}(x) = 8mx^{2m-1}\]
oh ok why does the m come down next to the 8 if it was a n exponent before.
because in general, the power rule is this if \[\Large f(x) = x^{n}\] then \[\Large f^{\prime}(x) = n*x^{n-1}\]
the 2m is part of the exponent, so in effect, n = 2m
oh ok thanks
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you're welcome
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