Question

help please!!

Using 10.0 g as the accepted value for the mass of the water, and the mass calculated using water's density in #6 above as the experimental value, calculate the percent error of your mass calculation, using the same formula as in #5 above.

(mass = 145.4

Answer 1

You got 14.54 grams for the mass when you *should* have gotten 10.0 grams for the mass (if all of the measurements were taken perfectly without error)

This is a difference of 14.54 - 10.0 = 4.54 grams

Divide this by the amount that you should have gotten (10.0) to get 4.54/10 = 0.454

then multiply by 100 to convert it to a percentage to get 45.4%

So the error is 45.4%

You can also use the formula found on this page to get the same answer

Answer 2

brilliant thats exactly what i got!!

Answer 3

that's great