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OpenStudy (anonymous):
find the derivative : f(x)=-5lnx
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jimthompson5910 (jim_thompson5910):
the derivative of ln(x) is 1/x and this is something you should memorize or write on a cheatsheet (or notecard)
jimthompson5910 (jim_thompson5910):
you pull out the constant, so you ignore that for now and derive ln(x) to get 1/x
then you reintroduce the constant back in
OpenStudy (anonymous):
alright i've seen that I just dont understand how it plays in with the -5
jimthompson5910 (jim_thompson5910):
that's a constant that can be ignored when you derive
jimthompson5910 (jim_thompson5910):
any constants can be pulled out
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jimthompson5910 (jim_thompson5910):
so you would derive
y = 22*ln(x),
y = 18*ln(x)
y = -33*ln(x)
all the same way
OpenStudy (anonymous):
ooooooohhh okay
OpenStudy (anonymous):
-5*1/x
jimthompson5910 (jim_thompson5910):
which becomes -5/x
jimthompson5910 (jim_thompson5910):
you got it
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OpenStudy (anonymous):
It'd be nice if my text would've just said that instead of going around in circles
jimthompson5910 (jim_thompson5910):
it probably did somewhere, but it just gave a convoluted way of saying it (with lots of notation attached)
OpenStudy (mathstudent55):
If k = constant and U = expression is x, then
d/dx(kU) = k * d/dx(U)
d/dx(-5lnx) = -5* d/dx(lnx) = -5 * (1/x) = -5/x
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