Question

hi there! ok unsure about my answer on this one. . .

9. Calculate the experimental value for density of the aluminum shot based on its mass (19.95) as well as its volume (8), using the following formula:
Density of Al = mass of Al shot/ volume of Al shot

Answer 1

So Density of Al = 19.95 - 8

Answer 2

I think you meant to say

Density of Al = 19.95/8

Answer 3

oops yes i did

Answer 4

divide that out to get your answer

Answer 5

im not understanding what to do after finding D = 2.5. . . .

Answer 6

is that the experimental value in itself?

Answer 7

that's the experimental density assuming 19.95 is the experimental mass and/or 8 is the experimental volume

Answer 8

if both are exact values, then it's not experimental (since nothing in an experiment is perfect)

Answer 9

thats why i was a bit confused. .. coz then i plug it into the next step of the equation which is: 10. If the accepted value for the density of aluminum is 2.70 g/mL, calculate the percent error of your density calculation, using the formula listed in #5 above.
/2.70 – 2.5/ * 100/ 2.70 =
.2/2.70 = .074 X 100 = 7.4& error of calculation

Answer 10

you should have gotten 2.49375 after you divide 19.95/8

Answer 11

wouldnt i round to 2.5?

Answer 12

|2.49375 - 2.7|
--------------- * 100
2.7


|-0.20625|
--------------- * 100
2.7


0.20625
--------------- * 100
2.7



0.07638888888889* 100


7.638888888889 %

Answer 13

So the error is roughly 7.638888888889 %

Answer 14

you could round to make things shorter to get 7.64%

Answer 15

where am i going wrong in my calculations? how did i end up with 7.41

Answer 16

you used 2.5 instead of 2.49375

Answer 17

so that explains the slight difference

Answer 18

thank you so much for your patience!

Answer 19

you're welcome