A long time ago Dulani found an island shaped like a triangle with three straight shores of length 3km, 4km and 5km. He said nobody could come within 1km of his shore. What was the area of his exclusion zone?
You basically have this triangle (which is the island itself)
then you add on this buffer zone of 1 km around the entire island
so you need to find the area of this red zone you can break it up into 3 rectangular pieces (shown in blue in this new attachment) and 3 circular sectors (shown in green)
do you see how to get the answer?
So like for the area of one of the rectangular pieces, do we just add 1km to each sides?
oh wait kinda get it
well the rectangular pieces are relatively easy to find 3*1 = 3 square km 4*1 = 4 square km 5*1 = 5 square km
so we have 3 separate areas of 3, 4, and 5 square km
this is all for the rectangular blue pieces
the green circular pieces are going to be trickier to find, but it's doable
you just need the central angles to find the area of each circular sector
so how do you find those?
is it you find the inside angle of the triangle and the you can find it? Using geometry..
more like trigonometry (since you'll use sine, cosine or tangent)
but yes, you find the inner angles of the triangle first
Ok thanks, i just got mixed up a little! We kept changing math teachers in school and they never really finish each chapters..
I gotcha, so how would you find the inner angles
i got 120 for the inner angle of the sector
the bottom left sector has an angle of 90 so that area is (90/360)*pi*1^2 = pi/4
the top sector has an angle of 360 - 90 - 90 - arctan(3/4) = 143.1301 degrees so the top sector has an area of (143.1301/360)*pi*1^2 = 0.39758*pi
finally, the bottom sector on the right has an angle of 360 - 90 - 90 - arctan(4/3) = 126.8699 degrees so the bottom right sector has an area of (126.8699/360)*pi*1^2 = 0.35242*pi
so we have these 3 areas for the 3 rectangular pieces: 3, 4, 5 and these 3 areas for the 3 circular pieces: pi/4, 0.39758*pi, 0.35242*pi add them up and tell me what you get
14.7
adding up pi/4, 0.39758*pi, 0.35242*pi, you should get pi/4+ 0.39758*pi+ 0.35242*pi = 3.1415926535898 which is basically pi (more or less)
this is because the circular sectors from each corner combine to make a circle of radius 1, which has an area of pi*r^2 = pi*1^2 = pi
so your total area is 3+4+5+pi = 12 + pi
12+pi is the total area of the shaded exclusion zone
Yes yes, thank you so much!
yw
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