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Mathematics 14 Online
OpenStudy (anonymous):

Differentiate \[f(x)=\sqrt{12x-x^3}\]

pooja195 (pooja195):

(x) = lim h -> 0 [f(x + h) - f(x)] / h = lim h -> 0 [ (x + h)^3 - 12(x + h) - x^3 + 12x] / h = lim h -> 0 [ x^3 + 3x^2h + 3xh^2 + h^3 - 12 x - 12h - x^3 + 12x ] / h = lim h-> 0 [ 3x^2h + 3xh^2 + h^3 - 12h ] / h =lim h -> 0 (3x^2 + 3xh + h^2 - 12) = 3x^2 - 12

OpenStudy (anonymous):

@billie4120 Do you know chain rule?

OpenStudy (anonymous):

\[\frac{d}{dx} (f(g(x))=f'(g(x))\times g'(x)\]

OpenStudy (anonymous):

ok yes so

OpenStudy (anonymous):

here \[f(x)=\sqrt x\] \[g(x)=12x-x^3\] Try now :)

OpenStudy (anonymous):

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