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lim(x^3-27)/(x-3) xarrow>3
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\[\lim_{x \rightarrow 3}\frac{x^3-27 }{ x-3}\]
The numerator is a difference of cubes; it can be factored. After factoring you will be able to cancel the common (x-3) factors in the numerator and denominator, remembering that x cannot equal 3. Then get your limit as usual....
I did that ans I got 27 is that correct
ooops. yeah its good :)
so then 27 is correct
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Yep
ok thanks
no prob
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