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Mathematics 17 Online
OpenStudy (anonymous):

lim(x^3-27)/(x-3) xarrow>3

OpenStudy (anonymous):

\[\lim_{x \rightarrow 3}\frac{x^3-27 }{ x-3}\]

OpenStudy (anonymous):

The numerator is a difference of cubes; it can be factored. After factoring you will be able to cancel the common (x-3) factors in the numerator and denominator, remembering that x cannot equal 3. Then get your limit as usual....

OpenStudy (anonymous):

I did that ans I got 27 is that correct

OpenStudy (anonymous):

ooops. yeah its good :)

OpenStudy (anonymous):

so then 27 is correct

OpenStudy (anonymous):

Yep

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

no prob

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