Find the derivative of F(x)=3x^2 algebraically using the definition of the derivative.
F(x)=3x^2 F(x) = 3(2)x^(2-1) F(x) = 6x^1 F(x) = 6x
that is all that it is asking for when it said algebratically it confussed me
are you currently in a section where you have to prove it using limits, epsilon proofs? the way i solved it above is how you normally solve it.
we are put we just got done learning it the way that you just did it
f ' = lim (h->0) ( f(x+h) - f(x) )/h
I am so confussed
Is the way that you did it algebrtically
no, it is using the definition of the derivative. first, if given f(x) = 3x^2 then f(x+h) = ....
right I need the algebratically using the definition of the derivative.
got it ?
I got f(3x^2+h)
nope. if given f(x) = 3x^2 then f(x+h) = 3(x+h)^2 u need expand it : f(x+h) = 3(x+h)^2 = 3(x^2+2xh + h^2) = 3x^2 + 6xh + 3h^2
ok
now, apply of them to defined of derivative using limit above f '(x) = lim (h->0) ( f(x+h) - f(x) )/h = lim (h->0) (3x^2 + 6xh + 3h^2 - 3x^2 )/h = lim (h->0) (6xh+3h^2 )/h so far so good ?
yes
now, can u simplify that if all thing in numerator divided by h
yes but you can;t simplify it anmore can you
so wouldn't tht be the answer
= lim (h->0) (6xh+3h^2 )/h = lim (h->0) 6xh/h + 3h^2/h = lim (h->0) 6x + 3h
ok got it and that is the answer correct.
just subtitute h=0, u got the answer right :)
you mean so the answer is 6x+3(0)
so then the answer is just 6x
yup
ok thanks
that is how to get derivative by using definition, it is always using limit you're welcome
thanks
yw again :)
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