Solve log3^3 + log3^x = 5.

Is it:
3log3 + xlog3 = 5
3xlog3 = 5
x ~ 3,5

? :/

Question

Solve log3^3 + log3^x = 5.

Is it: 
3log3 + xlog3 = 5
3xlog3 = 5
x ~ 3,5

? :/

openstudier · Answer

If you have two log with the same base and your adding them, that is the same thing as multiplying the terms together.

openstudier · Answer

$$\log _{a}b+\log_{a}c=\log_{a}bc$$

aravindg · Answer

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openstudier · Answer

$$\log3^{3}+\log3^{x}=5$$

openstudier · Answer

$$\log3^{3x}=5$$

openstudier · Answer

$$3xlog3=5$$

anonymous · Answer

and how do I find x?

openstudier · Answer

$$x=\frac{ 5 }{ 3\log3 }$$

raden · Answer

3^x * 3^3 not equal 3^(3x)
it is 3^(x+3), @OpenStudier

raden · Answer

well, i will use ur step above, @Haruhi

raden · Answer

log3^3 + log3^x = 5
3log3 + xlog3 = 5
xlog3 = 5 - 3log3
x = (5 - 3log3)/log3

it is, easy right ?

anonymous · Answer

Thanks so much! That helped a lot! So loga^x + loga^y is never = loga^xy? :/

raden · Answer

first, i  agree about the property like openstudier said above :
log_a b+log_a c =log_a (bc)

but, in the property of exponent. if given a*x times a*y then it can be a^(x+y) not a^(xy)

anonymous · Answer

Thanks!! ^-^

raden · Answer

you're welcome :D