Question

*****FAN AND MEDAL*********
HELP!!!!

Answer 1

Select the symbol that makes the number sentence true.
\[4^2/2^-3 (blank) \left| -2 \times 7 \right| \times \left| 2 - 10 \right|\]
\[A) < \]
\[B) > \]
\[C) =\]
\[D) \le \]
Sorry that took so long this is hard to do on a laptop XD

Answer 2

@Mertsj

Answer 3

is that 2 to the negative third power

Answer 4

yes

Answer 5

the answer is B

Answer 6

how did you get it?

Answer 7

\[\frac{4^2}{2^{-3}}|-2\times7|\times|2-10|\]

Answer 8

Is that the correct problem?

Answer 9

yes, I just couldnt do that on a laptop for some reson :/

Answer 10

yes the answer is B and the problem is correct

Answer 11

First of all, work on the fraction. Do you know that 1/a^-n=a^n?

Answer 12

@Mertsj I have no idea what 1/a^-n=a^n means...:/

Answer 13

its B the left side is 128 and the right side is 112

Answer 14

I know that it BI just want to know how to get it

Answer 15

\[\frac{4^2}{2^{-3}}=4^2(2^3)\]

Answer 16

Do you know this property:
\[\frac{1}{a ^{-n}}=a^n\]

Answer 17

yes..

Answer 18

So what is the left side?

Answer 19

you just solve for each side
you take 4 squared and divid that by 2 to the negative 3
and then you solve fr the other side

Answer 20

128?

Answer 21

Yes. 16 x 8 = 128

Answer 22

Now let's work on the right side.

Answer 23

-2 x 7 and since it absoute vaule you cant have a negative so it would be 14 , the ndo 2-10 and you would get 8 and multiply 14 by8
to get the value of that side

Answer 24

-2X14=

Answer 25

so then the other side would be 112, ok now I get it thank you @Mertsj

Answer 26

yw

Answer 27

Thank you @rolla you helped alot to :)

Answer 28

ur welcome :)
@Stabar