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Help proving a trig identity? (1-cos x)/(sin x) = (sin x)/(1 + cos x)
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taking the right hand side (sinx)/( 1+cosx) multiply the numerator and denominator by (1-cosx) sinx/(1-cosx) * (1-cosx) /(1-cosx)
Okay, doing that right now!
Okay so I get sin x (1-cosx) for the numerator & for the denominator 1-cos squared x
you will get sinx(1-cosx) /(1+cosx) (1-cosx) which will then give sinx (1-cosx) / (1- cos^2x)
Okay now I see how to get the final answer! Thanks so much!
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