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what is the derivative of 6^(lnx^2)
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\[\ln x^2 = 2lnx\]
so, yours y = 36^lnx. take ln both sides lny = ln 36^lnx = lnx * ln 36
take derivative is much more easier than original one. hope that helps
If you meant to say \[y=6^{(\ln x)^2},\] \[\ln y=(\ln x)^2\ln6\\ \frac{1}{y}y'=2\ln6(\ln x)\frac{1}{x}\\ y'=\ln36\frac{\ln x}{x}\cdot y\\ y'=\ln36\frac{\ln x}{x}\cdot 6^{(\ln x)^2}\]
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