when 50ml of gas of at 45 degrees celcius and 0.55atm is placed into 250ml flask the temperature is 32 degrees celcius, what is the new pressure?
PV=nRT use it
i dont know where to put what
i assume number of moles of gas is constant
\[ \frac{ P _{1} V _{1} }{ T _{1} }=\frac{ P _{2} V _{2}}{ T _{2} }\]
there we go :D thanks! :)
:D YW
oh theres one more
noooooooooooooo jk ;)
When 0.60 grams of H2 are places into 2500.0 ml flask with an undisclosed amount of Bromine(+2), the total pressure is 12.5atm. if the temperature is 27 degrees Celsius, how many grams of bromine are in the flask?
apparently im supposed to use more than just one gas law
again i think you have to use PV=nRT
you have, P,. you have to find n that is number of moles, you have temperature, you have gas constant that is R and you have volume just plug in and play :D
yea but im supposed to use more than one law
PV=nRT is just one law and earlier i made the comparison from one law in two cases
okay can you explain what this formula is:\[[P_{ob}+a\left({n\over V}\right)^2]\times(v-nb)=nRT\]
this is the general case of PV=nRT when your a and b=0 we get PV=nRT, hope you know what does a and b stands for
lol, i dont
awesome ;) google it :D lol
n--> number of moles
a and b are either determined empirically for each individual compound or estimated from the relations.
i looked it up n now im even more confused..this is not helping :(
\[a=\frac{ 27R^2T _{c}^2 }{ P _{c} }\]
and \[b=\frac{ RT _{c} }{ 8P _{c} }\]
Tc , Pc--> critical temperature and pressure
question! the Volume in PV=nRT has t be in liters, right?
umm yea
u dont seem sure..?
its been 5 years since i did it for the last time lol so kinda but generally you should use SI units so i think you can use liters or in this case go with ml , in physical chemistry we prefer ml
okay well i figured that i need to find the pressure of H2 and subtract it from the total then use that left over pressure to calculate the moles of Br n convert that to grams to find grams...yea?
yep :D if you have number of moles use \[n=\frac{ w }{ m }\] where w--> weight andn m--> molar mass
okay well can you work it out with me? im not getting the right answer for some reason :S
what is your number of moles?
0.3 for H2
then just plug in the values
i did \[P_{H_2}(2500)=(0.3)(0.08206)(300)~~\implies~~P_{H_2}=0.00295416\]\[12.5-0.00295416=12.49704584\]\[(12.49704584)(2500)=n(0.08206)(300)~~\implies~~n_{Br}=1269.096377\]and i know that's not right, given the balance equation \(Br_2+2h_2\rightarrow2BrH_2\)
@ghazi
if you use liters though, it gives 0.97 moles which is 77.45 grams...i have no idea what to go by..??
use liters
whenever you have wrong answer try to check if your answer is reasonable or not
thats what im trying to make sure of.. pressure of H2=2.954atm pressure of Br=9.56atm moles of H2=0.3mol moles of Br=0.97mol grams of H2=0.60g grams of Br=77.45g reasonable??
yea this seems reasonable :)
the question is worth 6pts out of 12...i cant afford it being wrong :P
so i hope you got right :)
k thanks a lot! :D
:D
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