Question

Pleeeeaase Pleeeeaaase help me?? Algebra 2... I've missed a few lessons and am completely lost :"(

Answer 1

What's your question

Answer 2

Show all work in dividing \[\frac{ 4t^2-1 }{ 15t+10 }\div \frac{ 4t^2-4t+1 }{ 3t^2+5t+2 }\]

Answer 3

use complete sentences to explain your process

Answer 4

were you able to get anywhere?

Answer 5

@jim_thompson5910 I am completely confuzzled :(

Answer 6

@Luis_Rivera I am desperate :(

Answer 7

the first step is to flip the second fraction and multiply

so you go from

\[\large \frac{ 4t^2-1 }{ 15t+10 }\div \frac{ 4t^2-4t+1 }{ 3t^2+5t+2 }\]

to

\[\large \frac{ 4t^2-1 }{ 15t+10 }\times \frac{ 3t^2+5t+2 }{ 4t^2-4t+1 }\]

Answer 8

Now combine the numerators and denominators to get


\[\large \frac{ (4t^2-1)(3t^2+5t+2) }{ (15t+10)(4t^2-4t+1) }\]


From here, you need to factor each expression as much as possible. Then cancel out the common terms and simplify.

Answer 9

so what do you get when you factor 4t^2 - 1

Answer 10

any ideas P.nut1996?

Answer 11

I don't remember how to factor:(

Answer 12

use the difference of squares rule

Answer 13

a^2 - b^2 = (a+b)(a-b)

Answer 14

2t^2 - 1

2t^2 - 1^2

so how would you use the rule above to factor?

Answer 15

if you're not sure, then a = 2t and b = 1

now just plug them into a^2 - b^2 = (a+b)(a-b)

Answer 16

Thank you so much for the help!! <3

Answer 17

that's not the full/final answer of course since you still need to factor and reduce

Answer 18

but you're welcome