Question

how to solve the following equation: csc^2x-4=0

Answer 1

Change csc^2x to 1/sin^2x

Answer 2

\[\frac{1}{\sin ^2x}=4\]

Answer 3

Now take reciprocals of both sides.

Answer 4

\[\sin ^2x=\frac{1}{4}\]

Answer 5

Now you can take it from there.

Answer 6

Do I take the square root?

Answer 7

yes

Answer 8

so, x=pi/6 and 5pi/6

Answer 9

no. sinx= + or - 1/2 so there is an answer in each quadrant.

Answer 10

so, x=pi/6,5pi/6,7pi/6 and 11pi/6

Answer 11

yes

Answer 12

Unless you want all the solutions in which case it would be your 4 answers + 2pi n

Answer 13

could you say :pi/6+npi,5pi/6+npi or pi/6+2npi,5pi/6+2npi

Answer 14

as a general solution...