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Statistics 19 Online
OpenStudy (anonymous):

how do you find the normal approximation?

OpenStudy (anonymous):

of wht

OpenStudy (anonymous):

one way of checking the effects of over coverage, nonresponse and other sources of the error in a sample survey is to compare the sample with known facts about the population About 24% of the Canadian population over 15 years of age they were born outside Canada The number X of the first generation Canadians in random samples of 1000 persons over 15 should therefore vary with the binomial (n=1000, p=.24) distribution

OpenStudy (anonymous):

use the normal approximation to find the probability that the sample will contain between 210 and 270 first generation Canadians

OpenStudy (anonymous):

70

OpenStudy (anonymous):

my bad can't do any stats...

OpenStudy (anonymous):

how did you get 70

OpenStudy (anonymous):

I believe the formula for this problem is p(x) = nCx (p^x) q^(n - x). Are you familiar with this?

OpenStudy (anonymous):

nooo

OpenStudy (anonymous):

p(x) = nCx (p^x) q^(n - x) use this formula and plug in the equation mam =)

OpenStudy (anonymous):

im still confused on what numbers to plug in

OpenStudy (anonymous):

Your problem has already given you all the numbers, such as n=1000, p=.24...

OpenStudy (anonymous):

well the other number I have is 13.5 we didn't go over this equation so I don't know what everything stands for

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