Find the period of the function f(x)=2cos(4x+3π)
In this case, because it's a circular function, the domain will go on forever unless you restrict it. So, in this case, going by the information, the domain is infinity. The range will be [-3, 1], because of the 2 in front of the cos. The period is how long the function takes to end up back where it started, or to make a full cycle. The period would be pi/2 for this.
\[T=\frac{2\pi}{b}=\frac{2\pi}{4}=\frac{\pi}{2}\]
for \[f(x)=asin(bx-c)+d\]
T=2πb=2π4=π2 this is just simple form of what i said
yeah just show the work... some people get mad about random answers as it doesn't really show the person that needs help
@Outkast3r09 where did you make use of the number 2 from the function at "2cos" and if yes where?
nope just used b as a is just the amplitude, it tells you how highs and lows (max and mins) of the sine function whereas the period is how many rads it takes to do a complete cycle
where is the "B" in this specific function?
\[f(x)=acos(bx-c)+d\]
T=2πb=2π4=π2
it's the coefficient infront of x
ok and something last. What did you mean in your previews respond when you said " for f(x)=asin(bx−c)+d" ?
I mean.... Every time I need to find a period I use this formula?
T = blabla?
t = F(x)
@Outkast3r09 Do I use this every time I wanna find a period? T=2πb=2π4=π2
yes mam
yes however the top will change. If you read Zoodude's explanation or mine . Period is the time it takes for the function to complete a full cycle. Sine and Cos both reach a complete cycle at 2 pi, whereas tan is at pi. the coefficient b affects the rads for completion of function
that is why T is the relation between normal period and the shrinking / stretching of the graph
so for tan and cot is T=π/b
?
yes
what about csc and sec?
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