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find the exact area of the surface obtained by rotating the curve about the x-axis. y=sqrt(1+5x) 1
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i tend to get these mixed up; length of a curve is ds, surface area is 2pi ds, accounting for y or x depending on axis rotated about right?
circumference of a circle is: 2pi r, and in this case r = y(x) ds amounts to the length of a line segment: ds = sqrt(x'^2+y'^2)
therefore the surface area is: \[\int_{1}^{7}2\pi~y(x)~ds\] \[2\pi\int_{1}^{7}y~\sqrt{1+(y')^2}~dx\]
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