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-9 sqrt/ over(4-7i)-(6-6i)
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\[\sqrt{-9}/(4-7i) - (6 - 6i)\] is that what its supposed to say?
Yes
please help me I dont know it
Okay well I'm not completely sure on how to do these anymore but I'm going to try my best. First thing I did was take out the parentheses to make this: 4-7i +6 +6i. I get the sqrt of -9/-2 - i after combing like terms.
I multiply by the conjugate (-2+i) to top and bottom.
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still confused what is the answer
By the way, the square root of -9 is 3i. On top I get: -6i + 3i^2 over 4 - i^2. Also known as -6i - 3 over 4 +1. i^2 is known as -1. Hang on I'm getting to the answer in the next step.
The answer should be: -6i-3/5 if I did this the right way.
Thank you so much :)
welcome
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