The integral f(x) = 3x/5 -2 from 0 to 5 should give the answer 3. I get -2,5 My attempt: F(x) = 3x² / 10 - 2x F(x) = 3*5² / 10 - (2 * 5) = -2,5
As you can see, along our interval, e^(x) > e^(-3x), so our integral will be: (e^(x) - e^(-3x)) * dx, from x = 0 to x = ln(5) The integral of e^(x) * dx is e^(x) The integral of e^(-3x) * dx is (-1/3) * e^(-3x) e^(x) - (-1/3) * e^(-3x) + C => e^(x) + (1/3) * e^(-3x) + C From 0 to ln(5) e^(ln(5)) - e^(0) + (1/3) * e^(-3 * ln(5)) - (1/3) * e^(-3 * 0) => 5 - 1 + (1/3) * 5^(-3) - (1/3) => 4 - 1/3 + (1/3) * (1/125) => 11/3 + 1/375 => (11 * 125 + 1) / 375 => (1375 + 1) / 375 => 1376/375 => 3.6693333333333333333333333333333
is that goood
integrate 3x/5 -2 ; [0,5] since this is a poly, the 0 is pointless to us; this IS a poly right? 3(5)^2/10 - 2(5) 3(25)/10 - 10 75/10 - 10 = 7.5 - 10 = -2.5
0 to 5, or 0 to ln(5)?
hmm, I must be missing something; the answer should be 3... :/
0 to 5
I don't know what you mean by a poly
of the form\[c_0+c_1x+c_2x^2+...+c_nx^n\] as opposed to a rational expression of some sort
poly is short for polynomial
hmm, no this is a straight line, so y = kx + m
a poly of degree 1 is a straight line
can you scan the problem? maybe your misreading something?
....or you might be looking at the wrong answer key, or the answer key may even have a wrong solution. That happens from time to time
I'm thinking the answer key seems to be wrong. There isn't much to misread and you seem to reach the same answer as me. So, I'm going to assume the answer 3 is wrong. Help appreciated. :)
http://www.wolframalpha.com/input/?i=integrate+3x%2F5-2+dx%2C+from+0..5 just as a dbl chk :) good luck
thx
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