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Trigonometry
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Find all solutions in the interval [0, 2π). sin2 x + sin x = 0
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\[\sin^2x+\sin x=0\\(\sin x)(\sin x+1)=0\\\text{so either }\sin x\text{ is 0 or -1.}\\\sin x=0\\x=0,\pi\\\sin x=-1\\x=\frac{3\pi}2\]
Thanks so much dude!
No problem... do you see what I did? Factor the expression and set factors equal to 0 -- solve for \(x\).
yeah, I see it now. Just couldn't remember it to save my life!
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