Ask your own question, for FREE!
Mathematics 24 Online
OpenStudy (anonymous):

What is the solution to the quadratic equation graphed below? A. x = -3 B. x = 4 C. x = -3 and x = 4 D. no real solution

OpenStudy (anonymous):

@Luis_Rivera

OpenStudy (whpalmer4):

The solutions are the values of x where the curve crosses the x-axis. Can you read the graph?

OpenStudy (anonymous):

?

OpenStudy (whpalmer4):

Look at the graph. Trace along the curve and find the spots where it crosses the x-axis, which is the line y=0. At each such spot, make note of the value of x. Those x values are the solutions.

OpenStudy (whpalmer4):

If the curve never crosses the x-axis, then choice (d) would be correct.

OpenStudy (anonymous):

I got B as my answer!

OpenStudy (whpalmer4):

Look at the curve again...does it only cross once?

OpenStudy (whpalmer4):

the wording is a bit deceptive, implying there is only one solution...but you know better, right? :-)

OpenStudy (phi):

Is this the exact question What is the solution to the quadratic equation graphed below? That does not make a lot of sense. But often, people want to know where the quadratic equation is equal to zero, in other words, what are its "roots" See attached.

OpenStudy (whpalmer4):

No, that's commonplace usage in most texts I've seen...

OpenStudy (phi):

if you are talking about a x^2 + bx +c =0 then yes. However, for y= a x^2 + bx +c you must specify a specify y value to solve for x. The min or max is an equally interesting point to solve for.

OpenStudy (anonymous):

So then our answer would be A?

OpenStudy (phi):

They want to know where the parabola crosses the x-axis. It crosses in 2 places. See attachment in the previous post.

OpenStudy (whpalmer4):

When speaking of solutions to a polynomial, it is customary to take y = 0.

OpenStudy (anonymous):

lol so then whats our answer guys lol

OpenStudy (anonymous):

really, no ones gona tell me the answer? ughh how sad..

OpenStudy (anonymous):

The answer is C -_-

OpenStudy (anonymous):

got C for my answer

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!