Question

Use the quadratic formula to solve the equation:
0 = x2 + x - 20
http://www.ppstest2.com/images2/AL9009.jpg
idk if you need that or not

Answer 1

\[x^2+x-20=0\]This is a quadratic equation of the form\[ax^2+bx+c\]Since the equation is set equal to zero, we can use the quadratic formula\[\frac{-b+/-\sqrt{b^2-4ac}}{2a}\]

Answer 2

Identify your a, b, and c values and substitute into the equation to solve for your two x solutions.

Answer 3

im alil confused lol

Answer 4

http://tutorial.math.lamar.edu/Classes/Alg/SolveQuadraticEqnsII.aspx

Skip down to the part about Quadratic Formula and read it

Answer 5

disclaimer: yes, you will have to read something and do practice examples and read the solutions before you fully understand the concept, welcome to mathematics please enjoy your stay

Answer 6

oh god yayyy lol

Answer 7

do not fret it only gets better

Answer 8

Does it help if I tell you\[x^2+x-20\]compare to\[ax^2+bx+c\]a =1, b = 1, c = -20

Answer 9

idont understand cuz i started in algebra 2 i didnt take algebra or algebra 1

Answer 10

A quadratic equation has an x^2, an x, and a constant term. Each part has a coefficient a, b, c.

Look at your quadratic equation. The coeffecient a of the x^2 term is 1. The coeffecient b of the x term is 1. The value of the c term is -20.

a = 1, b = 1, c = -20.

Know you PLUG THESE VALUES into your quadratic equation to obtain the solutions. The link I provided you shows how the quadratic formula was derived.

Answer 11

thank you !!!!1

Answer 12

\[\frac{-b+/-\sqrt{b^2-4ac}}{2a}\]a = 1, b = 1, c = -20\[\frac{-(1)+/-\sqrt{(1)^2-4(1)(-20)}}{2(1)}\]

Answer 13

You solve it