Find the area of the shaded sections. Click on the answer until the correct answer is showing.
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OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
is there a pic?
OpenStudy (anonymous):
jimthompson5910 (jim_thompson5910):
use the formula
A = (angle/360)*pi*r^2
jimthompson5910 (jim_thompson5910):
you'll have to find the area of each region separately, but they are congruent regions
so you basically find the area of one region, then double that answer
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OpenStudy (anonymous):
1/3(16(pi)
OpenStudy (anonymous):
16/3 (pi)
jimthompson5910 (jim_thompson5910):
A = (angle/360)*pi*r^2
A = (60/360)*pi*4^2
A = (1/6)*pi*16
A = (8/3)*pi
That's the area of one region. Double it to get 2*(8/3)*pi = (16/3)*pi
So you got it
OpenStudy (anonymous):
okay thank you :)
OpenStudy (anonymous):
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OpenStudy (anonymous):
and for this one?
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
same idea, the radius is still 4 but now the angle is 90 degrees (instead of 60 degrees)
jimthompson5910 (jim_thompson5910):
oh wait, they want the triangles, not the pie-shaped pieces
OpenStudy (anonymous):
how did you find out it was 90?
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jimthompson5910 (jim_thompson5910):
the area of one triangle is
A = b*h/2
A = 4*4/2
A = 8
OpenStudy (anonymous):
ohhhh nvm ik how
jimthompson5910 (jim_thompson5910):
so both triangles combined make 2*8 = 16 square units
jimthompson5910 (jim_thompson5910):
yeah it shows a right angle (slightly covered up though)
OpenStudy (anonymous):
so the answer is 16?
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OpenStudy (anonymous):
hwta happen to the other part?
jimthompson5910 (jim_thompson5910):
what do you mean
OpenStudy (anonymous):
what about the part of 90/360 (pi)
OpenStudy (anonymous):
what about this one
jimthompson5910 (jim_thompson5910):
Area of Shaded Region = (Area of Larger Circle) - (Area of Smaller Circle)
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OpenStudy (anonymous):
ohhh so like 16(pi)- 9(pi)
OpenStudy (anonymous):
Find the radius of a circle whose area equals the area of a rectangle that measures 2 ft. by 11 ft. (Use = 22/7)
OpenStudy (anonymous):
things are making much more sense to me noe
jimthompson5910 (jim_thompson5910):
more like 36pi - 9pi = 27pi
jimthompson5910 (jim_thompson5910):
but you have the right idea
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jimthompson5910 (jim_thompson5910):
what's the area of the rectangle?
OpenStudy (anonymous):
thats what i meant to say
OpenStudy (anonymous):
Find the radius of a circle whose area equals the area of a rectangle that measures 2 ft. by 11 ft. (Use = 22/7)
OpenStudy (anonymous):
ummmm hold on idk how to get the h in the problem i never do knowhow
OpenStudy (anonymous):
h=height
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jimthompson5910 (jim_thompson5910):
A = b*h
A = 2*11
A = 22
jimthompson5910 (jim_thompson5910):
that's the area of the rectangle
jimthompson5910 (jim_thompson5910):
now use this area to find the radius of the circle
jimthompson5910 (jim_thompson5910):
this site is bugging out...
jimthompson5910 (jim_thompson5910):
is it working for you?
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OpenStudy (anonymous):
the sie is working for me but im not sure how to get the correct answer i mean ik that (pi )(r)^2 equals the area but idk how to find the radius from the atinfo
OpenStudy (anonymous):
from that info *
jimthompson5910 (jim_thompson5910):
A = pi*r^2
22 = pi*r^2
solve for r
OpenStudy (anonymous):
sqrt7
jimthompson5910 (jim_thompson5910):
oh right and you use 22/7 for pi
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OpenStudy (anonymous):
right?
jimthompson5910 (jim_thompson5910):
22 = pi*r^2
22 = (22/7)*r^2
1 = (1/7)*r^2
7 = r^2
r = sqrt(7)
you got it
OpenStudy (anonymous):
Find the difference in area between the circle and the triangle. Click on the answer until the correct answer is showing.
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
you need to find the area of the circle and the triangle
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OpenStudy (anonymous):
okay area of the circle is 9(pi)
jimthompson5910 (jim_thompson5910):
good
OpenStudy (anonymous):
but how do i get h for the triangle idk how to find h for the problem A=1/2( b)(h)
jimthompson5910 (jim_thompson5910):
you would use trig to find the base and height of that triangle
OpenStudy (anonymous):
the base is 9 right ?
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jimthompson5910 (jim_thompson5910):
cos(60) = adj/hyp
cos(60) = adj/6
adj = 6*cos(60)
adj = 3
So the shorter leg is 3 units
jimthompson5910 (jim_thompson5910):
the longer leg is 6*sin(60) = 6*sqrt(3)/2 = 3*sqrt(3)
jimthompson5910 (jim_thompson5910):
therefore, the area of the triangle is
A = b*h/2
A = 3*(3*sqrt(3))/2
A = 9*sqrt(3)/2
OpenStudy (anonymous):
wouldnt it 9 (pi)-9/2 sqrt 3
jimthompson5910 (jim_thompson5910):
yep
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jimthompson5910 (jim_thompson5910):
that's the exact area
OpenStudy (anonymous):
okay one more i think
OpenStudy (anonymous):
Leave answer in exact form unless otherwise indicated.
Find the area of the region between a regular hexagon with sides of 6" and its inscribed circle.
OpenStudy (anonymous):
how do i find the area of the hexagon?
jimthompson5910 (jim_thompson5910):
one sec, the drawing wasn't working out but I found a better drawing
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OpenStudy (anonymous):
okie dokie :)
jimthompson5910 (jim_thompson5910):
ok here is a hexagon
jimthompson5910 (jim_thompson5910):
you can break it up into 6 pieces like so
jimthompson5910 (jim_thompson5910):
so each piece is a triangle with a base of 6 inches
at this point, the height is unknown, but we can find it
jimthompson5910 (jim_thompson5910):
each interior angle is 180(6-2)/6 = 120 degrees. Split that in half to get 60 degrees
So each triangle has 60 degrees in the lower portion like this
|dw:1363047088184:dw|