Question

given y=4x^2-2x+(2), find the equation of the tangent line that is horizontal to the curve

Answer 1

You can differentiate it first

Answer 2

and you get 8x-2

Answer 3

what do you do after

Answer 4

you can try equating dy/dx=0 then solve for x

Answer 5

dy/dx=8x-2
8x-2=0
x=1/4

Answer 6

so
y=4x^2-2x+(2)
y=4(1/4)^2-2(1/4)+2
y=7/4

Answer 7

how do we put it in slope intercept form?

Answer 8

then use
\[y-y_1=m(x-x_1)\]

Answer 9

whats m=?

Answer 10

so the final answer is?

Answer 11

equation of tangent line is y=7/4

Answer 12

thanks!

Answer 13

can you help me with one more problem?